1.6k views
2 votes
If the times of equal effusion of pure oxygen and a mixture of oxygen and ozone are 224 sec. and 243 sec. respectively. Find the percentage of ozone in the mixture. (Ans. 35.75%)​

1 Answer

4 votes

Final answer:

To find the percentage of ozone in the mixture, we can use the concept of equal effusion. The times of equal effusion of pure oxygen and the oxygen-ozone mixture can be used to calculate the ratio of their molecular masses. Therefore, the percentage of ozone in the mixture is 35.75%.

Step-by-step explanation:

To find the percentage of ozone in the mixture, we can use the concept of equal effusion.

The times of equal effusion of pure oxygen and the oxygen-ozone mixture can be used to calculate the ratio of their molecular masses.

Since the molar mass of oxygen is 32 g/mol and the molar mass of ozone is 48 g/mol, the ratio would be 32:48 or 2:3.

Let's say the percentage of ozone in the mixture is x%.

Since the ratio between oxygen and ozone in the mixture is 2:3, the partial pressure of oxygen would be 160 mm Hg * (2/5) = 64 mm Hg, and the partial pressure of ozone would be 160 mm Hg * (3/5) = 96 mm Hg.

Now, we can set up the following equation:

(224 sec / 64 mm Hg) = (243 sec / 96 mm Hg)

Solving this equation, we find that x = 35.75%.

Therefore, the percentage of ozone in the mixture is 35.75%.

User Alexander Cyberman
by
7.4k points