Final answer:
The correct option is (a). The frog population after 3 years will be 1.5 million, calculated by adding the yearly increase of 450 thousand to the initial population of 150 thousand three times.
Step-by-step explanation:
The question deals with a straightforward arithmetic progression, which is a sequence of numbers where the difference between consecutive terms is constant. In this case, the population of frogs in a Crowley is increasing by a constant number of 450 thousand frogs per year. To find the population after 3 years, we will add this yearly increase three times to the initial population.
Initial population: 150 thousand
Yearly increase: 450 thousand
- After 1 year: 150 thousand + 450 thousand = 600 thousand
- After 2 years: 600 thousand + 450 thousand = 1050 thousand
- After 3 years: 1050 thousand + 450 thousand = 1500 thousand
Therefore, the frog population after 3 years will be 1.5 million, which corresponds to option (a).