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How do you find the oxidation numbers of atoms in a molecule that contains O, H, and a halogen?

A) By assigning a fixed oxidation number to hydrogen
B) By taking the charge of the oxygen atom
C) By determining the number of valence electrons in the halogen
D) By consulting the periodic table

User Ebt
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1 Answer

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Final answer:

To determine oxidation numbers in a molecule, apply several rules such as hydrogen typically being +1, oxygen -2 (except in peroxides, or when bound to fluorine), and halogens generally -1 (unless combined with oxygen), ensuring that the sum of oxidation numbers equals the charge on the molecule or ion.

Step-by-step explanation:

To find the oxidation numbers of atoms in a molecule containing oxygen (O), hydrogen (H), and a halogen, you can follow these general rules:

  • Hydrogen is usually assigned an oxidation number of +1 except when it forms compounds with metals (where it can be -1).
  • Oxygen is typically assigned an oxidation number of -2, but in peroxides, it has an oxidation number of -1. When bonded to fluorine, oxygen can have a positive oxidation number.
  • Halogens such as fluorine (F), chlorine (Cl), bromine (Br), and iodine (I) usually have negative oxidation numbers (-1), but when they are combined with oxygen, their oxidation numbers can be positive.
  • The sum of oxidation numbers in a neutral molecule must be 0, and in a polyatomic ion, it must equal the ion's charge.

Examples: In H2O, hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2. For halogens in a molecule like HCl, hydrogen would still be +1, while chlorine would be -1. In polyatomic ions like chlorate (ClO3-), chlorine would have an oxidation number of +5 and oxygen would have -2.

User Daniel Williams
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