Final answer:
The magnitude of linear motion represents the speed of an object and each velocity value given (8 m/s, 4 m/s, 6 m/s, 2 m/s) reflects its magnitude. The correct answer to the problem provided, according to kinematic equations and Newton's second law, is 'c. A body with a mass of 2 kg is acted upon by a force of 4 N. The acceleration of the body is 2 m/s²'.
The correc option is d.
Step-by-step explanation:
The question asks to find the magnitude of linear motion given four different velocities: 8 m/s, 4 m/s, 6 m/s, and 2 m/s.
The magnitude of linear motion refers simply to the speed of the object in motion.
Thus, each of the velocities listed (a) 8 m/s, (b) 4 m/s, (c) 6 m/s, and (d) 2 m/s, represents the magnitude of the linear motion for each scenario respectively.
Now let's take a look at the given problem options and find the one which is solved correctly using kinematic equations:
a. This statement is incorrect because the final velocity using the kinematic equation v = u + at (where u is initial velocity, a is acceleration, t is time) would be 0 + (4 m/s²)(2 s) = 8 m/s.
b. This statement is incorrect for the same reason as option a; the correct final velocity is 8 m/s.
c. According to Newton's second law, F = ma (where F is force, m is mass, a is acceleration), the acceleration a is F/m, which in this case is 4 N / 2 kg = 2 m/s². Therefore, this statement is correct.
d. This option is incorrect as per the calculation shown in option c.
Therefore, the correct option that uses kinematic equations successfully is c. A body with a mass of 2 kg is acted upon by a force of 4 N. The acceleration of the body is 2 m/s².
The correc option is d.
Your complete question is: A particle is moving along a circular path with a constant speed of 10ms−1. What is the magnitude of the change in velocity of the particle, when it moves through an angle of
60∘ around the centre of the circle?