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A pitcher can throw a 0.145 kg ball with the same momentum as a 3 g bullet at v = 1.5 x 10^3. What is the speed of the baseball?

a) 870 m/s
b) 1740 m/s
c) 435 m/s
d) 217.5 m/s

1 Answer

4 votes

Final answer:

The speed of a baseball with the same momentum as a bullet with mass 0.003 kg moving at 1.5 x 10^3 m/s is 31.034 m/s, which is not one of the provided options.

Step-by-step explanation:

The student's question pertains to the concept of momentum, which is a fundamental concept in physics. Momentum (p) is the product of an object's mass (m) and its velocity (v), given by the equation p = m * v. The question specifically asks for the speed of a baseball when it has the same momentum as a bullet.

We are given that a bullet with mass 3 g (or 0.003 kg) has a speed of 1.5 x 103 m/s. To find the speed of the baseball, which has a mass of 0.145 kg, we first calculate the momentum of the bullet.

Bullet momentum: p = m * v = 0.003 kg * 1500 m/s = 4.5 kg*m/s

To find the baseball's speed, we set its momentum equal to the bullet's momentum and solve for the baseball's velocity:

Baseball momentum: p = 0.145 kg * vbaseball = 4.5 kg*m/s

Solving for vbaseball:

vbaseball = 4.5 kg*m/s / 0.145 kg = 31.034 m/s

Thus, none of the given options a) 870 m/s, b) 1740 m/s, c) 435 m/s, d) 217.5 m/s are correct. The speed of the baseball is 31.034 m/s when it has the same momentum as the bullet.

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