Question

How many grams are in 2.49 x 10^24 atoms of Hg?

Answer 1

`m_(Hg)=829.4gHg`

Step-by-step explanation:

Hello there!

In this case, considering the Avogadro's number, which helps us to realize that 1 mole of mercury atoms contains 6.022x10²³ atoms and at the same time 1 mole of mercury weights 200.59 g, we obtain:

`m_(Hg)=2.49x10^(24)atoms*(1mol)/(6.022x10^(23)atoms) *(200.59g)/(1molHg)\\\\m_(Hg)=829.4gHg`

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