Final answer:
The correct answer is A) 50HP, 460V, Wye-Delta winding - 60 A.
Step-by-step explanation:
The correct answer is A) 50HP, 460V, Wye-Delta winding - 60 A.
For a three-phase motor with a known winding type, horsepower, and voltage, we can use the formula I = (sqrt(3) * P) / (V * EFF), where I is the full load current, P is the power in HP, V is the voltage, and EFF is the efficiency of the motor. In this case, for option A, we have:
I = (sqrt(3) * 50) / (460 * EFF)
If we assume an efficiency of 90% for the motor, we can calculate the full load current:
I = (sqrt(3) * 50) / (460 * 0.9) = 60 A
Therefore, the correct answer is A) 50HP, 460V, Wye-Delta winding - 60 A.