Final answer:
During an action potential, sodium ions contribute to depolarization in the adjacent area.
Step-by-step explanation:
The influx of sodium ions from the current action potential contributes to depolarization in the adjacent area.
During an action potential, sodium ion channels open, allowing sodium ions to rush into the cell, which increases the positive charge inside the cell and leads to depolarization. This depolarization propagates in a wave down the length of the axon.
Therefore, option b. Sodium ions contribute to depolarization, is the correct answer.