Question

What is the frequency of the radiation emitted by a hydrogen atom when an electron transitions from n=2 to n=1 given that the energy difference between the two levels is 1.64 x 10^-14 J?

A) 4.56 x 10^14 Hz
B) 9.12 x 10^14 Hz
C) 1.64 x 10^14 Hz
D) 3.28 x 10^14 Hz

Answer 1

The frequency of the radiation emitted by a hydrogen atom when an electron transitions from n=2 to n=1 is 2.48 × 10^14 Hz.

Step-by-step explanation:

To determine the frequency of the radiation emitted by a hydrogen atom when an electron transitions from n=2 to n=1, we can use the energy difference between the two levels. We can use Planck's constant to relate the energy difference to the frequency of the radiation:

E = hf

Where E is the energy difference, h is Planck's constant (6.626 × 10^-34 J-s), and f is the frequency. Rearranging the equation:

f = E/h = (1.64 × 10^-14 J) / (6.626 × 10^-34 J-s) = 2.48 × 10^14 Hz

Therefore, the frequency of the radiation emitted by the hydrogen atom is 2.48 × 10^14 Hz.