Answer:
1.2m/s
Step-by-step explanation:
Using the law of conservation of energy
m1u1+m2u2 = (m1+m2)v
v is the common velocity after collision
Substitute the given values
3(2) + 2(0) = (3+2)v
6 + 0 = 5v
v = 6/5
v = 1.2m/s
Hence the velocity of the white ball after the collision is 1.2m/s