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When an object is submerged in a fluid, it experiences an upward force called buoyancy. This force is equal to the weight of the fluid displaced by the object. If an object displaces 2 liters of water (density = 1000 kg/m³), what is the buoyant force acting on the object?

a. 20 N
b. 10 N
c. 2 N
d. 0.2 N

1 Answer

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Final answer:

The buoyant force can be calculated using Archimedes' principle. For 2 liters of water displaced, the force is 19.62 N, so the closest answer is 20 N.

The correct option is A.

Step-by-step explanation:

The concept we are dealing with here is known as Archimedes' principle, which describes the behavior of objects when submerged in a fluid. According to this principle, the buoyant force acting on a submerged object is equal to the weight of the fluid displaced by the object.

For an object displacing 2 liters of water, we can calculate the buoyant force using the density of water and the acceleration due to gravity (9.81 m/s²). Density (1000 kg/m³) multiplied by volume (2 liters or 0.002 m³) multiplied by gravitational acceleration yields the weight of the displaced water, which is also the buoyant force.

Calculation:
Fb = ρ * V * g
Fb = 1000 kg/m³ * 0.002 m³ * 9.81 m/s²
Fb = 19.62 N

Therefore, the closest answer to the buoyant force acting on the object is 20 N, which corresponds to choice (a).

The correct option is A.

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