Question

A plane taxies onto the runway, preparing for take off. It starts at rest before it's engines start. The plane's top speed, before it takes off the ground, is about 8820 km/s. If the take off takes about 32.8s, what is the acceleration of the plane?

Answer 1

Step-by-step explanation:

This is a fast plane! At it's takeoff speed, it could fly around the world in 5 seconds!

Acceleration is defined as the change in speed over the change in time.

`a = (v_f - v_o)/(t)`

Where v_f is the final velocity, v_o is the original velocity, and t is the time.

We know v_f = 8820km/s.

v_o = 0 km/s. The plane "starts at rest before it's engine start." So we know it starts from zero velocity.

t = 32.8 seconds.

You can solve the equation from there.