Yes, I have the balanced equation for the combustion of C3H8. It is:
C3H8 + 5O2 → 3CO2 + 4H2O
From the balanced equation, we can see that 1 mole of C3H8 reacts with 5 moles of O2. Therefore, to find the number of moles of O2 needed to burn 5.0 moles of C3H8, we multiply 5.0 moles by the mole ratio:
5.0 moles C3H8 × 5 moles O2 / 1 mole C3H8 = 25 moles O2
To convert moles of O2 to grams, we need to know the molar mass of O2, which is approximately 32 g/mol. Multiplying the number of moles by the molar mass gives us the mass of O2:
25 moles O2 × 32 g/mol = 800 grams of O2
Therefore, 800 grams of oxygen are needed to burn 5.0 moles of C3H8.m