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In ABC find a if b = 2, C = 6, and A=35°

Show work plzz!!!!

2 Answers

10 votes

This problem cannot satisfy the triangle inequality. The triangle cannot be constructed and therefore solved.

a = 35

b = 2

c = 6

b+c ≤ a

2 + 6 ≤ 35

41 ≤ 35

The sum of the lengths of sides b, c must be greater than the length of the remaining side a.

User Vermis
by
7.5k points
6 votes

Answer:


a=1.749

Explanation:

Recall Law of Sines


(sin(A))/(a)=(sin(B))/(b)=(sin(C))/(c)

Solve for angle B


A^\circ+B^\circ+C^\circ=180^\circ\\35^\circ+B^\circ+6^\circ=180^\circ\\41^\circ+B^\circ=180^\circ\\B^\circ=139^\circ

Determine side "a" given angle B and side "b"


(sin(35)^\circ)/(a)=(sin(139^\circ))/(2)\\ asin(139^\circ)=2sin(35^\circ)\\a=(2sin(35^\circ))/(sin(139^\circ))\\ a\approx1.749

User Riccardo Cedrola
by
7.0k points