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How much work did Jim do? What kind of energy does the box gain? If there’s no friction, how much energy does the box gain?

How much work did Jim do? What kind of energy does the box gain? If there’s no friction-example-1
User CampbellMG
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Slim Jim does 227.5 Joules of work on the box, resulting in the box gaining both kinetic and potential energy (if applicable). If there's no friction, the total energy gain includes both kinetic and potential energy.

To calculate the work done by Slim Jim, we use the formula:

Work = Force × Distance × cos(θ)

where:

Force (Force) = 35 N (applied force)

Distance (Distance) = 6.5 m (distance pulled)

θ is the angle between the force and the direction of motion (assumed to be 0 degrees for simplicity, as we don't have information on the angle).

Work = 35 N × 6.5 m × cos(0 degrees)

Work = 227.5 Joules

The box gains kinetic energy as a result of Slim Jim's work. According to the work-energy theorem, the work done on an object is equal to the change in its kinetic energy. Therefore, the box gains 227.5 Joules of kinetic energy.

If there's no friction, and assuming no other forms of energy are involved, the box would also gain potential energy due to its change in height (if it is lifted) or lose potential energy if it is lowered. In this scenario, the total energy gain would be the sum of the kinetic and potential energy.

User ChuanRocks
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