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A projectile is fired from ground level with an initial speed of 650 m/sec and an angle of elevation of 30 degrees. Use that the acceleration due to gravity is 9.8 m/sec2m/sec2. (a) The range of the projectile is meters. (b) The maximum height of the projectile is meters. (c) The speed with which the projectile hits the ground is 650 m/sec.

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Answer:

(a) The range of the projectile is 37,336.3 m

(b) The maximum height of the projectile is 5,389.03 m

Step-by-step explanation:

Given;

initial velocity of the projectile, u = 650 m/s

angle of projection, θ = 30⁰

(a) The range of the projectile is calculated as;


R = (u^2sin 2\theta)/(g) \\\\R = ((650^2)Sin (2* 30^0))/(9.8) \\\\R = 37,336.3 \ m

(b) The maximum height of the projectile is calculated as;


H = (u^2sin^2\theta)/(2g) \\\\H = ((650^2)(Sin \ 30^0)^2)/(2* 9.8) \\\\H = ((650^2)(0.5)^2)/(19.6) \\\\H = 5,389.03 \ m

User Ella Sharakanski
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