Question

What is the mass (in grams) of 9.7 x 10ˆ24 atoms of copper?

a) 1.03 x 10ˆ3 g
b) 63.5 g
c) 96.7 g
d) 63.5 x 10^24 g

Answer 1

The mass of 9.7 x 10^24 atoms of copper is 1.03 x 10^3 g.

Step-by-step explanation:

To find the mass of 9.7 x 1024 atoms of copper, we need to use the atomic mass of copper and Avogadro's number. The atomic mass of copper is 63.54 g/mol. Avogadro's number is 6.02 x 1023 atoms/mol. So, the mass of 1 mole of copper is 63.54 g. Therefore, the mass of 9.7 x 1024 atoms of copper is:

(9.7 x 1024 atoms) / (6.02 x 1023 atoms/mol) x (63.54 g/mol) = 1.03 x 103 g.