Question

A typical lamp emits huge numbers of photons each second. A lamp emits 22 J of yellow light with wavelength 580 nm in 1 second. Calculate the number of photons that accounts for 22 J of energy.

a) 2.06 x 10^19 photons
b) 3.78 x 10^17 photons
c) 9.50 x 10^19 photons
d) 6.4 x 10ˆ19 photons

Answer 1

The number of photons that account for 22 J of energy is a) 2.06 x 10^19 photons.

Step-by-step explanation:

To calculate the number of photons that account for 22 J of energy, we can use the formula E = nhf, where E is the energy, n is the number of photons, h is Planck's constant (6.63 × 10-34 J·s), and f is the frequency of the light. We can rearrange the formula to solve for n by dividing both sides by hf:

n = E /hf

Substituting the given values, we have:

n = (22 J) / ((6.63 × 10-34 J·s)(3.00 × 108 m/s) / 580 × 10-9 m)

n = 2.06 × 10^19photons.