Question

****Python Please***

problem 2 Linked List:

2.1. Write a function, def remove(list1: LinkedList, n: int)-> LinkedList:
remove ()function accepts a LinkedList and an integer, n. Remove the n-th node from the Linked list and
return the resulting LinkedList. If n is greater than the length of the linked list, return None (20 pts).

Answer 1

The remove() function deletes the n-th node from a Python linked list. If n is larger than the list size, it returns None. The process includes pointer traversals and link adjustments for removal.

Step-by-step explanation:

Implementing the remove() function to delete the n-th node from a linked list in Python involves traversing the list until the desired node is reached and then modifying the links to exclude that node. If n is larger than the size of the list, the function should return None.

Here is a step-by-step explanation of how the function could be implemented:

1. Check if the list is empty or if n is less than or equal to zero, and if so, return the unmodified list or None.
2. Initialize two pointers, one to track the current node and one as a previous node.
3. Traverse the list, moving both pointers until the n-th node is reached, keeping in mind to decrease the count of n with each iteration.
4. Once the n-th node is found, adjust the previous node's next pointer to skip the current node, effectively removing it from the list.
5. If n is greater than the number of nodes, return None to indicate the operation cannot be completed.
6. Finally, return the head of the modified list.

It is crucial to handle edge cases, such as removing the head or the last node of the list, which would require additional checks and pointer adjustments.