Final answer:
The statement is false because replacing edge costs with their squares does not necessarily preserve the minimum-cost path.
Step-by-step explanation:
The statement is false. Replacing each edge cost c by c² will not necessarily preserve P as a minimum-cost s-t path for the new instance. To illustrate this, consider the following counterexample:
- Assume a directed graph G with two vertices s and t connected by two edges: (s, x) with cost 2 and (x, t) with cost 4.
- Let P be the path (s, x, t) with total cost 6, which is the minimum-cost s-t path for G.
- If we replace each edge cost c by c², the new instance will have edge costs 4 (2²) and 16 (4²).
- A new path (s, x, t) still exists in the new instance, but its total cost is now 20 (4+16), which is greater than the previous minimum cost of 6. Therefore, P is not a minimum-cost s-t path for the new instance.