Question

Assume that a char variable takes 1 byte. char arx[] = "Kean University Computer Science"; char "ptr1 = arr; char *ptr2 = arx +6;

(1) what is the ptr2 - ptr1?
(2) Write two different printf) statements in C to print out the "U" character?

Answer 1

In C, the difference between pointers ptr2 and ptr1 is 6 bytes. To print the 'U' character from the given array, two printf statements can be: printf("%c", *(arx + 7)); and printf("%c", arx[7]);.

Step-by-step explanation:

The question concerns the C programming language and specifically deals with operations on pointers and printing characters using the printf function in C.

1. Difference between ptr2 and ptr1

Since a char variable takes 1 byte, ptr2 - ptr1 will give us the difference in bytes between the two. As ptr2 is initialized to point to the 7th character of the array (considering index starts from 0), and ptr1 is initialized to point to the first character of the array, the difference will be 6 bytes.

2. Printing the 'U' character

There are multiple ways to print the 'U' character in C. Two ways are:

printf("%c", *(arx + 7)); - This statement uses pointer arithmetic to print the character in the 8th position where 'U' is located.

• printf("%c", arx[7]); - This is an alternative using array indexing to achieve the same result.