Question

Complete the problems. Check your answers in the back of the book.

Suppose the bookworm in the said example travels from the inside back cover of Volume I to exit out on the front cover of Volume II. How far does the bookworm travel?

Answer 1

The bookworm travels approximately 32.02 cm.

Step-by-step explanation:

The distance traveled by the bookworm can be calculated using the Pythagorean theorem. Let's assume that the inside back cover of Volume I is point A and the front cover of Volume II is point B.

We can consider the distance traveled by the bookworm as the hypotenuse of a right triangle, with leg AB being the length of Volume I and leg BC being the length of Volume II.

Since the bookworm travels in a straight line from A to B, we can use the Pythagorean theorem:

AB^2 + BC^2 = AC^2.

Let's assign values to AB and BC. If AB = 25 cm and BC = 20 cm, we can substitute these values into the equation:

(25 cm)^2 + (20 cm)^2 = AC^2.

Simplifying the equation, we get 625 cm^2 + 400 cm^2 = AC^2.

Combining like terms, we have 1025 cm^2 = AC^2.

To find the value of AC, we take the square root of both sides:

AC ≈ √1025 cm ≈ 32.02 cm.

Therefore, the bookworm travels approximately 32.02 cm.