Question

Assuming 'A' Is Any 16-Bit Variable With Some Value, What Does The Execution Of The Following Statement (For Sure) Does To A? A∣=(3<<5); A. Sets All The Bits Except Bits 5 And 6 B. Resets Bits 5 And 11 C. Sets Bits 5 And 11 D. Sets Bits 5 And 6

Answer 1

The execution of the statement 'A |= (3<<5);' in C programming sets bits 5 and 6 of variable A.

Step-by-step explanation:

The execution of the statement A |= (3<<5); in C programming performs a bitwise OR operation between the value of 'A' and the result of shifting the binary representation of 3 five positions to the left. This means that the bits 5 and 6 of 'A' will be updated based on the values of the corresponding bits in the binary representation of 3.

Since the binary representation of 3 is '0000000000000011', shifting it five positions to the left results in '0000000000110000'. When performing a bitwise OR with 'A', this will set bits 5 and 6 of 'A' to 1 if they were originally 0, but will not change the values of the other bits in 'A'.

Therefore, the correct answer is D. Sets Bits 5 and 6.