Question

Assume initially, $ to =0×10010100, and $ s0 =0×B3A39383

What is the value (in decimal) of $51 after executing the following code:
SW $s0, 0($t0)
​lb $s1,0($t0)

Answer 1

The value of $51 after executing the code depends on the byte loaded from memory location 0.

Step-by-step explanation:

To determine the value of $51 after executing the given code, we need to understand what the code does step by step.

1. SW $s0, 0($t0): This instruction stores the value of $s0 in the memory location pointed to by $t0.
2. lb $s1,0($t0): This instruction loads a byte from the memory location pointed to by $t0 into $s1.

Since $t0 is initially 0, these instructions essentially store the value of $s0 in the memory location 0 and then load a byte from that same memory location into $s1. Therefore, the value of $51 after executing the code is the byte that is loaded from memory location 0.