Question

1)Write an equation for the formation of aluminium chloride from its elements.

2)An aluminium chloride molecule reacts with a chloride ion to form the AlCl4− ion. Name the type of bond formed in this reaction. Explain how this type of bond is formed in the AlCl4−ion.
Type of bond .
Explanation
3)Aluminium chloride has a relative molecular mass of 267 in the gas phase. Deduce the formula of the aluminium compound that has a relative molecular mass of 267
4) Deduce the name or formula of a compound that has the same number of atoms, the same number of electrons and the same shape as the AlCl4

Answer 1

The equation for the formation of aluminium chloride is 2 Al + 3 Cl2 → 2 AlCl3. The bond formed in the reaction with a chloride ion is a coordinate covalent bond. The formula of the aluminium compound with a relative molecular mass of 267 is Al2Cl6. A compound with the same number of atoms, electrons, and shape as AlCl4 is CCl4.

Step-by-step explanation:

1) The equation for the formation of aluminium chloride from its elements is: 2 Al + 3 Cl2 → 2 AlCl3.

2) The type of bond formed in the reaction between an aluminium chloride molecule and a chloride ion to form the AlCl4− ion is a coordinate covalent bond. This type of bond is formed when both bonding electrons come from the same atom.

3) To deduce the formula of the aluminium compound that has a relative molecular mass of 267, we need to calculate the molar mass of aluminium chloride (AlCl3), which is 133.33 g/mol. Dividing the relative molecular mass by the molar mass gives us the formula Al2Cl6.

4) A compound that has the same number of atoms, the same number of electrons, and the same shape as the AlCl4 ion is carbon tetrachloride (CCl4).