Final answer:
The probability of offspring being AaBbcc in a cross between AABBCc and AaBbCc is 6.25%, and the probability of offspring being AABBCC is 12.5%, using the product rule of probability.
Step-by-step explanation:
To determine the probability of the offspring being AaBbcc or AABBCC in a cross between AABBCc and AaBbCc, we need to consider each gene separately and use the product rule of probability.
For the first gene (A/a), the possible combinations for Aa offspring are AA x Aa and Aa x Aa, which yields a probability of 0.5.
For the second gene (B/b), to have Bb offspring, the combinations are BB x Bb and Bb x Bb, resulting in a probability of 0.5.
However, for cc offspring, since one parent is Cc and the other is Cc, there's a 0.25 probability of obtaining cc.
Multiplying these separate probabilities together, the likelihood of an AaBbcc offspring is
0.5 * 0.5 * 0.25 = 0.0625 or 6.25%.
Similarly, for AABBCC offspring, the probability is calculated as follows:
For AA, it is 0.5, for BB it is 0.5, and for CC it is 0.5.
Therefore, the cumulative probability for AABBCC would be
0.5 * 0.5 * 0.5 = 0.125 or 12.5%.
In conclusion, the probability of having an AaBbcc offspring is 6.25%, and an AABBCC offspring is 12.5%.