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Aqueous potassium carbonate was mixed with aqueous copper(I) fluoride, and a crystallized copper(I) carbonate product was formed. A crystalized product is a solid. The other product, potassium fluoride, remains dissolved in solution. Consider the other product and its phase, and then write the balanced molecular equation for this precipitation reaction.

User Mehatab
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Final answer:

The balanced molecular equation for the reaction where aqueous potassium carbonate is mixed with aqueous copper(I) fluoride to form crystallized copper(I) carbonate and potassium fluoride is K2CO3(aq) + 2CuF(aq) → Cu2CO3(s) + 2KF(aq).

Step-by-step explanation:

When aqueous potassium carbonate is mixed with aqueous copper(I) fluoride, a double-replacement reaction occurs, resulting in the formation of crystallized copper(I) carbonate as a precipitate and aqueous potassium fluoride.

A salt metathesis reaction, sometimes called a double displacement reaction, is a chemical process involving the exchange of bonds between two reacting chemical species which results in the creation of products with similar or identical bonding affiliations

To write the balanced molecular equation for this reaction, the insolubility of the copper(I) carbonate must be taken into account as per the rule that all carbonates except those of potassium, sodium, and ammonium are insoluble.

The balanced molecular equation for the precipitation reaction is: K2CO3(aq) + 2CuF(aq) → Cu2CO3(s) + 2KF(aq)

Here, the solid (s) denotes the precipitate formed, which is copper(I) carbonate, and (aq) denotes the compounds that remain dissolved in the aqueous solution, such as potassium fluoride.

User Joey Roosing
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