Question

What is the output of the following lines of code?

int x=7;
do{

System.out.println(x);

x=(x%2==0)? x-1: x-3;

}while (x>1);

Answer 1

The provided Java code outputs the numbers 7, 4, and 3 sequentially, as it uses a do-while loop and a ternary operator that checks if 'x' is even and decrements it accordingly until 'x' is no longer greater than 1.

Step-by-step explanation:

The output of the provided code snippet, which is written in Java, can be determined by understanding the behavior of the do-while loop and the ternary operator used within it. The loop will execute at least once and will only continue if the condition at the while statement is true. Given the initial value x=7, the loop prints out the value of x and then applies the ternary operator, which checks whether x is even: if it is, x is decremented by 1, otherwise by 3. This proceeds until x is no longer greater than 1. Let's go through the loop step-by-step:

1. Output 7, x becomes 4 since 7 is not even (7-3=4).
2. Output 4, x becomes 3 since 4 is even (4-1=3).
3. Output 3, x becomes 0 since 3 is not even (3-3=0).

The loop stops because x is no longer greater than 1. Thus, the final output is:

• 7
• 4
• 3