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Let P(A) = 0.5, P(B) = 0.4, P(A ∩ B) = 0.14. Try to find P(A | B').

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Final answer:

To calculate P(A | B'), we determined P(A AND B') as P(A) - P(A ∩ B). Then, we found P(B') by subtracting P(B) from 1, and finally divided P(A AND B') by P(B') to obtain P(A | B') = 0.6.

Step-by-step explanation:

The student is asking to calculate the conditional probability P(A | B'), which is the probability of event A occurring given that event B does not occur. To find this, we can use the formula for conditional probability: P(A | B') = P(A AND B') / P(B'). Since we know that P(A ∩ B) = 0.14, we can find P(A AND B') by subtracting P(A ∩ B) from P(A), which gives P(A AND B') = P(A) - P(A ∩ B) = 0.5 - 0.14 = 0.36. The probability of B' (not B) is 1 - P(B), which is 1 - 0.4 = 0.6. Now, we can calculate P(A | B') as P(A AND B') / P(B') = 0.36 / 0.6 = 0.6

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