Final answer:
The first equation has no reaction. The second equation forms fluoride ions and chlorine gas. The third equation forms chloride ions and iodine. The fourth equation has no reaction.
Step-by-step explanation:
For the first equation, Br2(aq) + 2F(aq) → no reaction because there is no known reaction between bromine (Br2) and fluorine (F).
For the second equation, F2(aq) + 2Cl(aq) → 2F^- (aq) + Cl2 (aq) because fluorine (F2) reacts with chlorine (Cl) to form fluoride ions (F^-) and chlorine gas (Cl2).
For the third equation, Cl2(aq) + 2I^- (aq) → 2Cl^- (aq) + I2 (aq) because chlorine (Cl2) reacts with iodide ions (I^-) to form chloride ions (Cl^-) and iodine (I2).
For the fourth equation, 12(aq) + 2Cl^- (aq) → no reaction because there is no known reaction between the 12 ions and chloride ions.