Question

How much 95% isopropyl alcohol and sterile water in milliliters will be needed to prepare 1 gallon of sterile 75% isopropyl alcohol? a) 757.08 ml of 95% isopropyl alcohol and 252.92 ml of sterile water

b) 500 ml of 95% isopropyl alcohol and 500 ml of sterile water
c) 750 ml of 95% isopropyl alcohol and 250 ml of sterile water
d) 800 ml of 95% isopropyl alcohol and 200 ml of sterile water

Answer 1

To prepare 1 gallon of sterile 75% isopropyl alcohol, approximately 6328 mL of 95% isopropyl alcohol and 252.92 mL of sterile water are needed.

Step-by-step explanation:

To prepare 1 gallon (3.785 L) of sterile 75% isopropyl alcohol, we need to calculate how much 95% isopropyl alcohol and sterile water are needed.

Let's assume x represents the volume of 95% isopropyl alcohol needed. The volume of sterile water needed will be 3.785 - x.

Using the volume percentage equation, we can set up the following equation:

x * 0.95 + (3.785 - x) * 0 = 3.785 * 0.75

Simplifying the equation, we get:

0.95x = 2.83875 - 0.75x

Combining like terms, we get:

1.7x = 2.83875

Dividing both sides by 1.7, we get:

x = 1.67

To convert gallons to milliliters, we multiply by 3785:

x = 1.67 * 3785 = 6327.95 mL

Therefore, we need approximately 6328 mL of 95% isopropyl alcohol and 3785 - 6327.95 = 252.92 mL of sterile water.