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Suppose there are two stations, A and B, that are 50,000 km apart and are connected by a forward link of R = 10 Mb/s. Assume that the propagation velocity over the link is 2.5 × 108 m/s. Note that the Mbits units below denote megabits; i.e., x 106.

to. Calculate the product of the delay times the bandwidth. __________Mbits

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Final Answer:

The product of the delay times the bandwidth is 2.0 Mbits.

Step-by-step explanation:

The delay is the time it takes for a signal to travel from station A to station B. The bandwidth is the amount of data that can be transmitted over the link per unit of time. The product of the delay times the bandwidth is a measure of the amount of data that can be transmitted over the link during the time it takes for a signal to travel from station A to station B.

In this case, the delay is 0.2 seconds and the bandwidth is 10 Mbps. Therefore, the product of the delay times the bandwidth is 2.0 Mbits.

Here are the calculations:

delay = distance / propagation_velocity

delay = 50,000,000 meters / 2.5 × 10^8 meters/second

delay = 0.2 seconds

bandwidth = 10 Mb/s

product = delay * bandwidth

product = 0.2 seconds * 10 Mb/s

product = 2.0 Mbits

Therefore, the product of the delay times the bandwidth is 2.0 Mbits.

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