Question

Belore every fight, the plot must verly that the tokal weight of the load is less than the maxmum allowable load for the archat. The alcraft can cary A0 passengens, and a fight has fuel and baggage that alowe for a botal passenger losd of 6,600 ob the plot sees that the plave is ful and at passengers are men. The airuaf wil be corertoaded it the mean weight of the passengers is diserthed with a mean of 1768 ib and a standand deviation of 39 The probablity is apgroumately (Round to four decimal places as neteded.)

Answer 1

To find the probability that the mean weight of the passengers is greater than the maximum allowable load, use the Z-score formula to convert the maximum allowable load into a Z-score. Then, use a Z-table or calculator to find the probability associated with that Z-score.

Step-by-step explanation:

The question is asking for the probability that the mean weight of the passengers on the aircraft is greater than the maximum allowable load. To solve this, we can use the normal distribution, since we are given the mean and standard deviation of the passenger weights. We need to find the probability that the mean weight is greater than the maximum allowable load of 6600 lbs.

We can use the Z-score formula to convert the maximum allowable load to a Z-score. The Z-score formula is Z = (X - μ) / σ, where X is the value we want to convert, μ is the mean, and σ is the standard deviation.

Once we have the Z-score, we can use a Z-table or a calculator to find the probability associated with that Z-score. The probability we are looking for is the area to the right of the Z-score on the normal distribution curve.