Final answer:
The probability of winning for the first time on the third attempt in a McDonald's Monopoly game with a 1 in 4 chance of winning each time is
9/64.
Step-by-step explanation:
If the McDonald's Monopoly game has a 1 in 4 chance of winning, the probability of winning on any given attempt is 1/4.
To find the probability of winning for the first time on the third attempt, you need to calculate the probability of not winning on the first two attempts and then winning on the third attempt.
The probability of not winning on one attempt is 3/4 (since there is a 1 in 4 chance of winning). Therefore, the probability of not winning on the first two attempts is (3/4) * (3/4) = 9/16.
Now, the probability of winning on the third attempt is (1/4).
To find the probability of winning on the third attempt, given that you didn't win on the first two attempts, you multiply these probabilities:
(9/16) * (1/4) = 9/64
So, the probability of winning for the first time on the third attempt is 9/64.