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Y=-4x-2;(4,-4)Write the equation in slope intercept form of the line that is perpendicular to the graph of the equation and passes through the given point.

User Jay Patel
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To find the perpendicular line to y = -4x - 2 passing through (4, -4), calculate the negative reciprocal slope of 1/4 and use the point-slope form to derive the new line's equation, which is y = (1/4)x - 5.

To find the equation of the line perpendicular to y = -4x - 2 that passes through the point (4, -4), we must identify the slope of the given line and use the fact that the slopes of perpendicular lines are negative reciprocals of each other. The given line has a slope of -4. The slope of the perpendicular line will then be the negative reciprocal, which is 1/4.

Using this slope and the point (4, -4), we can apply the point-slope form: y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point the line passes through. Let's substitute the values into this equation:

y + 4 = (1/4)(x - 4)

Simplify to get the equation in slope-intercept form (y = mx + b):

y + 4 = (1/4)x - 1

Subtract 4 from both sides:

y = (1/4)x - 5

This is the equation of the line perpendicular to y = -4x - 2 passing through the point (4, -4) in slope-intercept form.

User Suzanshakya
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