Question

Here are equations showing the relationship between cost of kents (x) and cost of alabers (y) : 10x+5y=35, x+8y=41. slove them

Answer 1

To solve the system of equations 10x + 5y = 35 and x + 8y = 41, we can use the elimination method. After aligning and subtracting the equations, we find y = 5. Substituting y back into one of the original equations gives us x = 1.

Step-by-step explanation:

The equations 10x + 5y = 35 and x + 8y = 41 represent a system of linear equations. To solve for x (cost of kents) and y (cost of alabers), we can use the substitution or elimination method. Let's use the elimination method:

1. Multiply the second equation by 10 to line up the x-coefficients: 10x + 80y = 410.
2. Now subtract the first equation from this new equation: (10x + 80y) - (10x + 5y) = 410 - 35.
3. This simplifies to 75y = 375. Divide both sides by 75 to find y: y = 5.
4. Substitute y = 5 into the second original equation: x + 8(5) = 41.
5. Simplify the equation: x + 40 = 41, then solve for x: x = 1.

Therefore, the solution to the system of equations is x = 1 and y = 5.