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A 23 kg child goes down a straight slide inlcined at 38 degrees above the horizantol. The child is acted on by his weight, the normal force from the slide, and the kinetic friction. How large is the normal force on the child?

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Final answer:

The normal force on a child going down an inclined slide is found by multiplying the child's weight by the cosine of the angle of inclination. With a mass of 23 kg and an angle of 38 degrees, the normal force can be calculated using the formula N = mg * cos(θ). The force is calculated as 215.27N.

Step-by-step explanation:

To find the normal force on a child going down a slide inclined at a certain angle, we need to consider the components of the gravitational force acting on the child.

The child's weight (gravitational force) can be split into two components: one perpendicular to the slide (which is the normal force) and one parallel to the slide (which contributes to the child's acceleration down the slide).

The weight of the child is given by W = mg, where m is the mass of the child and g is the acceleration due to gravity. The normal force, N, is given by N = W * cos(θ), where θ is the angle of inclination of the slide.

Calculating the weight of the child, we get W = 23 kg * 9.8 m/s²

= 225.4 N.

The normal force is then N = 225.4 N * cos(38°).

=215.27N

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