Question

C++ please Integer valueln is read from input. Write a while loop that iterates until valuein is negative. At each iteration. - Update integer finalVal as follows. - If valuein is divisible by 3, output "lose" and do not update finaIVal - Otherwise, output 'win' and increment finalval.

Answer 1

The C++ while loop iterates as long as 'valuein' is non-negative, outputs 'lose' if divisible by 3, does not update 'finalVal', and outputs 'win' otherwise incrementing 'finalVal'.

Step-by-step explanation:

The subject of this question is writing a while loop in C++ that iterates until a given integer, valuein, is negative. During each iteration, if valuein is divisible by 3, the loop must output "lose" and not update finalVal. Otherwise, it should output "win" and increment finalVal. Here's a C++ code snippet demonstrating this loop:

int finalVal = 0;
while(valuein >= 0) {
if(valuein % 3 == 0) {
cout << "lose" << endl;
} else {
cout << "win" << endl;
finalVal++;
}
// Read next valuein (This code assumes the next value is read here)
}

When valuein is divisible by 3, the program outputs "lose" and moves on to the next iteration without changing finalVal. If it's not divisible by 3, "win" is printed and finalVal is incremented by one