Final answer:
The number of nodes created for each inserted string in a trie depends on whether the characters in the string match parts of previously inserted strings. A new node is created for each character that doesn't already exist in the trie at the needed position. Overlapping character sequences reduce the number of nodes required.
Step-by-step explanation:
The number of nodes created for each inserted string in a data structure depends on the type of data structure being used. Assuming the question is related to a trie, which is a tree-like data structure that stores a dynamic set of strings, usually used for retrieving a key in a dataset of strings. Each character of the string corresponds to a node in the trie.
When you insert a string into a trie, you create a new node for each character that does not already have a corresponding node at the appropriate level in the trie. If some of the initial characters in the string already exist as a path in the trie (from the root node down), then fewer nodes are created as you only need to add nodes for the characters that are missing. For example, if you insert the word 'cat' into an empty trie, three nodes are created, one for each letter. If you then insert the word 'car', only one new node needs to be created for the letter 'r' because the 'ca' part is shared with 'cat'.
Therefore, the exact number of nodes required for each inserted string varies depending on the overlap it has with already inserted strings. Additionally, if you insert a string that is already in the trie, no new nodes are required.