Final answer:
The maximum link utilization with a window size of 255 on a 2,000,000 bps satellite channel with a 270-ms delay is 0.0001%.
Step-by-step explanation:
Maximum Link Utilization
To calculate the maximum link utilization, we need to consider the frame length, channel capacity, and round trip time (RTT). The frame length is given as 2000 bits, the channel capacity is 2,000,000 bps, and the RTT is 270 ms (which is equivalent to 0.27 seconds).
The utilization can be calculated using the formula: Utilization = (Frame Length / Channel Capacity) * (1 / (RTT + Transmission Time)).
Substituting the given values, we get: Utilization = (2000 / 2,000,000) * (1 / (0.27 + (2000 / 2,000,000))) = 0.000001
Therefore, the maximum link utilization is 0.000001 or 0.0001%.