Final answer:
The solutions to the quadratic equation x^(2)+3x-4 x+3 are x = 1 and x = -4.
Step-by-step explanation:
The given expression represents a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = 3, and c = -4. To find the solutions, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
Substituting the values, we get:
x = (-(3) ± √((3)² - 4(1)(-4))) / (2(1))
Simplifying further, we get:
x = (-3 ± √(9 + 16)) / 2
x = (-3 ± √25) / 2
x = (-3 ± 5) / 2
Therefore, the solutions to the quadratic equation are x = 1 and x = -4.