Final answer:
To construct a binary tree from preorder (CABDIHKMEFGJLNO) and inorder (AIDBKHMCFEJNLOG) traversals, use the preorder to identify the root and inorder to separate the subtrees. The root is 'C', creating left (AIDBKHM) and right (FEJNLOG) subtrees. The post-order traversal for this binary tree is IDHKMBALFGJEONC.
Step-by-step explanation:
The question revolves around constructing a binary tree from given preorder and inorder traversals, and then determining its post-order traversal. Preorder traversal is CABDIHKMEFGJLNO and inorder traversal is AIDBKHMCFEJNLOG. We use the preorder to determine the root and its left and right subtrees, and the inorder to know which nodes are in the left subtree and which are in the right subtree.
The root of the tree is the first element in the preorder, which is 'C'. Now, looking at the inorder traversal, 'C' divides it into left subtree (AIDBKHM) and right subtree (FEJNLOG). Next, we take 'A' from the preorder as the root for the left subtree and so on, continuing the process recursively. Unfortunately, due to the limitations of this response format, I cannot draw the tree, but you denote it with a hierarchical structure.
The post-order traversal is the sequence of nodes visited after the left and right subtrees have been traversed, ending with the root node. By applying the definition of post-order traversal to this specific binary tree, the post-order sequence would be: IDHKMBALFGJEONC.