Final answer:
To write an assembly program that takes a user input and prints multiples of the number up to 100 using x86 assembly language and NASM assembler.
Step-by-step explanation:
To write an assembly program that takes a user input and prints multiples of the number up to 100, you can use the x86 assembly language and the NASM assembler. Here is an example program:
section .data
prompt db 'Enter a number: ', 0
section .text
global _start
_start:
; Print prompt
mov eax, 4
mov ebx, 1
mov ecx, prompt
mov edx, 15
int 0x80
; Read user input
mov eax, 3
mov ebx, 0
mov ecx, number
mov edx, 2
int 0x80
; Convert input to integer
movzx eax, byte [number]
sub eax, '0'
; Multiply and print multiples
mov ebx, eax
mov ecx, eax
loop:
mul ecx
mov eax, edx
; Print the multiple
mov eax, 4
mov ebx, 1
mov ecx, multiple
mov edx, 20
int 0x80
; Check if multiple reached 100
cmp eax, 100
jle loop
; Exit program
mov eax, 1
xor ebx, ebx
int 0x80
section .data
number: db 0
multiple: db ' ', 0
This assembly program uses the x86 instruction set architecture and the NASM assembler. It first prompts the user to enter a number, reads the user input, and converts it to an integer. Then, it multiplies the number by itself and prints the result as long as it is less than or equal to 100. Once the program reaches 100, it exits.