Final answer:
When x = 7 and y = 8, 4y^0 + x^1 is equal to 11.
Step-by-step explanation:
To evaluate the expression 4y^0 + x^1 when x = 7 and y = 8, we substitute the given values into the expression. Since any number raised to the power of 0 is equal to 1, we can substitute 1 for y^0. So, 4y^0 + x^1 becomes 4(1) + 7^1.
Calculating, 4(1) + 7^1 = 4 + 7 = 11.
Therefore, when x = 7 and y = 8, 4y^0 + x^1 is equal to 11.