Question

2. A block of addresses is granted to some organization. We know that the addresses are as below:

i) 222.51.66.39/27
ii) 192.168.100.12/29
iii) 200.100.50.20/25
What are the network address and broadcast address of these block? Pls show your calculations.

Answer 1

To find the network address, perform a bitwise AND operation between the IP address and the subnet mask. To find the broadcast address, set all the host bits to 1 based on the subnet mask. The calculated network and broadcast addresses vary based on the given subnet masks for each IP block.

Step-by-step explanation:

The question asks about determining the network address and the broadcast address for a given block of IP addresses using subnet masks. The subnet mask indicates which part of the IP address represents the network and which part represents the host. To calculate these, we perform bitwise AND operation between the IP address and the subnet mask for the network address, and set all host bits to 1 for the broadcast address based on the provided subnet.

Calculations

• 222.51.66.39/27: Here, the subnet mask is 255.255.255.224. The network address is 222.51.66.32 and the broadcast address is 222.51.66.63.
• 192.168.100.12/29: The subnet mask is 255.255.255.248. The network address is 192.168.100.8 and the broadcast address is 192.168.100.15.
• 200.100.50.20/25: The subnet mask is 255.255.255.128. The network address is 200.100.50.0 and the broadcast address is 200.100.50.127.

These values are found by converting the IP addresses and subnet masks to binary, performing the necessary operations, and then converting back to decimal format.