Final answer:
The print_bits() function in C can be implemented by iterating through each bit of a uint8_t number and printing it after bitwise manipulation to isolate and display each bit as '0' or '1'. Leading zeros are added for numbers with fewer than 8 bits.
Step-by-step explanation:
The task is to implement the function print_bits() in C programming language. This function will receive a single uint8_t value as a parameter and must print that value as an 8-bit binary string, with the most significant bit first. To ensure all 8 bits are always printed, leading zeros must be added for numbers that do not otherwise fill the full 8 bits.
Here's a possible implementation of the print_bits() function in the given bit.c file:
void print_bits(uint8_t value) {
for(int i = 7; i >= 0; i--) {
putchar('0' + ((value >> i) & 1)); }}
This code snippet uses a for loop to iterate through each bit of the input uint8_t number from the most significant to least significant bit. It shifts the value to the right 'i' times to bring the desired bit to the least significant position and then applies a bitwise AND operation with 1 to isolate it. The resulting bit is then printed as either '0' or '1'.