Final answer:
There are 24 different ways the four passengers can arrange themselves in a socially distanced row for purchasing tickets, calculated using the factorial of 4 (4!).
Step-by-step explanation:
The question asks for the number of ways four passengers can arrange themselves in a row for buying a ticket while observing social distancing. In a mathematical context, this is a permutation problem. However, due to the nature of the question and its connection to social distancing, we must consider that there is enough space between each passenger. Assuming there is one way to place each passenger in a socially distanced manner, the number of arrangements for the four passengers would be 4! (4 factorial), which is the product of all positive integers up to 4.
Thus, the calculation is as follows:
- 4! = 4 × 3 × 2 × 1
- 4! = 24
There are 24 different ways the four passengers can arrange themselves in a socially distanced row for purchasing tickets.