Final answer:
The total time taken by a 50 MByte POST operation over a 150 Mbps connection without any processing or queuing delay is approximately 2.67 seconds, with the assumption that the response time is negligible.
Step-by-step explanation:
If the web client sends a completed form using POST method to the web server on an already established persistent HTTP connection, and the size of the message carrying the POST method is 50 MBytes, we need to calculate the total time taken for this POST operation to complete, including the time for the HTTP 200 OK response to be received by the client. Since the link rate is 150 Mbps and we are assuming there is zero processing and queuing delay, we can calculate the transfer time by converting the size of the message to bits and then dividing by the link rate.
To start, we convert 50 MBytes to bits:
50 MBytes * 8 bits/byte = 400 Mbits
Next, we calculate the transfer time:
400 Mbits / 150 Mbps = 2.67 seconds
Since the time for the response to travel back is also needed, but not specified, for simplicity we can assume that the response size is negligible compared to the upload size or covered within the calculated time. Thus, the total time is approximately 2.67 seconds. It's important to note that in a real-world scenario, there will typically be some processing and queuing delays, and the response time might not be negligible.