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Ite the solution set in interva (1)/(3)x<-1 or 6x>0 -3

User Capoeira
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Final answer:

The solution to the inequalities (1/3)x < -1 or 6x > -3 is found by solving each inequality separately, giving x < -3 and x > -1/2, respectively. Therefore, the solution set in interval notation is (-∞, -3) ∪ (-1/2, ∞).

Step-by-step explanation:

The problem involves finding the solution set where either (1)/(3)x < -1 or 6x > -3. To find the solutions, we solve each inequality separately.

For the first inequality, we multiply both sides by 3 to isolate x:

  • 3*(1/3)x < 3*(-1)
  • x < -3

For the second inequality, we divide both sides by 6:

  • 6x/6 > -3/6
  • x > -1/2

The solutions to the inequalities are x < -3 and x > -1/2. Because these are joined by 'or,' the complete solution set is the union of both sets:

  • x < -3
  • x > -1/2

Therefore, in interval notation, the solution is (-∞, -3) ∪ (-1/2, ∞).

User JC Brand
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