Question

Overflow and Underflow

Question 4) Create a new C++ file named: overAndUnder.cpp

In the file create variable of data type short named largeNumber. Assign the value of 32767 to it. Create another short variable named lowNumber, assign the value of -32765 to it.

Display the value of the variable largeNumber.

Now display the value of the variable largeNumber +5.

What is the result? Answer:

Display the value of the variable lowNumber.

Now display the value of the variable lowNumber - 30.

What is the result? Answer:

Question 5) Assume that a certain fakeType data type holds values between 0 and 50.

Assume that we have one variable myNumber that holds the value of 48. What will be the values of the following?

fakeType newNumber = myNumber + 5;

fakeType anotherNumber = 4 – 10;

fakeType someNumber = myNumber + 20;

fakeType finalNumber = myNumber – 60;

User input

Answer 1

In C++, the data type short can hold 16-bit signed integers. The range of values that can be stored in a short variable is from -32,768 to 32,767. The given code demonstrates the usage of short variables and their behavior when performing arithmetic operations. The fakeType data type holds values between 0 and 50, and the given expressions are evaluated accordingly.

Step-by-step explanation:

In C++, the data type short can hold 16-bit signed integers. The range of values that can be stored in a short variable is from -32,768 to 32,767.

In the given code, the variable largeNumber is assigned the value 32,767 and the variable lowNumber is assigned the value -32,765. When we display the value of largeNumber and largeNumber + 5, the result will be 32,767 and -32,763 respectively.

For the second part of the code, where the data type fakeType holds values between 0 and 50, we can evaluate the expressions as follows:

1. newNumber = myNumber + 5 will be 53.
2. anotherNumber = 4 - 10 will be -6.
3. someNumber = myNumber + 20 will be 68.
4. finalNumber = myNumber - 60 will be -12.